Here, in Italy, we must to center 6 numbers in a set of 90! You win if you get 3, 4, 5, and obviously 6 numbers. But .....what are the probabilities to win in comparison with the probabilities to loose? We're going to assume the classical definition of probability regarding the possibility that a single event happens: �Number of matching cases divided by Number of all possible cases. In our scenario we will have theese situations: 6 extracted number over 90 with i success and 6-i missing, with variable i that goes from i=0 (None of my number corresponds to the extracted ones) to i=6: BINGOO JACKPOT!!!!

So starting from this formula, we.....

.....we are able to calculate the probabilities of every situation!

- P(i=0) = 1/1.533 --> ~ 65.2%

- P(i=1) = 1/3.361 --> ~ 29.7%

- P(i=2) = 1/21.51 --> ~ 4.64%

- P(i=3) = 1/326.7 --> ~ 0.306%

- P(i=4) = 1/83015284 --> ~ 1.20E-6%

- P(i=5) = 1/148241578 --> ~ 6.74E-7%

- P(i=6) = 1/622614630 --> ~ 1.60E-7%

So... it was told that you start to win with i=3 and if someone just wishes to reach 4 numbers of 6.... well..ya know....you'd betta incriz yo 'ass....man!!!!! talking about the JACKIEP situation, well....image that you and your brotha are chineese and you won the 1st price of the NATIONAL lottery, extracetd from 1.2 bilions of people 2x622milions= 1.2 bilions!!!!!!!

Deeeeeiiiiioooooouuuuuu

Well this is the Italian situation. If you want to calculate your local Bingo's probabilities, use the same formula keeping in mind this: 90 stands for all set of numbers, 6 stands for the number of value extracted, 84=90-6 stands for all remaing numbers NOT extracted, i stands for generic numbers that you match from the 6 ones extracted, 6-i stands for generic numbers that you don't match from the 6 ones extracted.

I.E. if in your local Bingo you need to get 5 numbers from a set of 60 then the probability to match 3 numbers over 5 will be:

Try to calculate p(i=4)=...... now!

Cheers by inerd.it rulez!

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